(x+3)(2x^2-4x-7)=0

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Solution for (x+3)(2x^2-4x-7)=0 equation: 


Simplifying
(x + 3)(2x2 + -4x + -7) = 0

Reorder the terms:
(3 + x)(2x2 + -4x + -7) = 0

Reorder the terms:
(3 + x)(-7 + -4x + 2x2) = 0

Multiply (3 + x) * (-7 + -4x + 2x2)
(3(-7 + -4x + 2x2) + x(-7 + -4x + 2x2)) = 0
((-7 * 3 + -4x * 3 + 2x2 * 3) + x(-7 + -4x + 2x2)) = 0
((-21 + -12x + 6x2) + x(-7 + -4x + 2x2)) = 0
(-21 + -12x + 6x2 + (-7 * x + -4x * x + 2x2 * x)) = 0
(-21 + -12x + 6x2 + (-7x + -4x2 + 2x3)) = 0

Reorder the terms:
(-21 + -12x + -7x + 6x2 + -4x2 + 2x3) = 0

Combine like terms: -12x + -7x = -19x
(-21 + -19x + 6x2 + -4x2 + 2x3) = 0

Combine like terms: 6x2 + -4x2 = 2x2
(-21 + -19x + 2x2 + 2x3) = 0

Solving
-21 + -19x + 2x2 + 2x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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